Flex+CUDA-graph closes gap to vLLM across batch sizes
Expanded benchmark sweep with the flex_attention + paged-KV path: | Batch | LoRA | vLLM tok/s | flex tok/s | flex / vLLM | |-------|------|-----------:|-----------:|------------:| | 32 | no | 7224 | 2189 | 30 % | | 32 | yes | 4581 | 2334 | 51 % | | 64 | yes | 7775 | 4279 | 55 % | | 128 | no | 14996 | 6501 | 43 % | Before this PR, transformers CB topped out at 9.2 % of vLLM on the reference (batch 32 + LoRA) workload. The flex path reaches 51 % on the same config and 55 % at batch 64. Details in scripts/benchmarks/results/flex_vs_vllm.md plus raw stats for each run. Output coherence verified by sampling the first three completions; see `sample_completions` in the stats JSONs. qwen3_flex_inference.py: added sample_completions + decode_tps_best to the output JSON so the PR writeup can cite both median and steady-state numbers without rerunning. Memory: flex uses 44-81 GB depending on batch, vs vLLM's 156 GB at every configuration. That's half to a fifth of vLLM's footprint. Remaining gap is kernel-level (vLLM uses FlashInfer / TRTLLM kernels tuned for sm_100, flex uses Inductor-generated Triton) plus chunked prefill (flex still does separate prefill passes per new batch). Closing those is out of scope for this PR.
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7 changed files with 218 additions and 1 deletions
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@ -629,7 +629,14 @@ def main():
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)
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med = sorted(wall_times)[len(wall_times) // 2]
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best = min(wall_times)
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peak = torch.cuda.max_memory_allocated() / 1024**3
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# Sample a couple of completions so we can eyeball coherence.
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sample_completions = []
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for s in out[:3]:
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sample_completions.append(
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tok.decode(s.output_ids[:80], skip_special_tokens = True)
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)
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res = {
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"backend": "qwen3_flex",
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"capture_cudagraph": args.capture_cudagraph,
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@ -638,9 +645,12 @@ def main():
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"n_decoded_tokens": total_decoded,
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"wall_times_s": wall_times,
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"median_wall_s": med,
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"decode_tps": total_decoded / med if med else 0,
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"best_wall_s": best,
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"decode_tps_median": total_decoded / med if med else 0,
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"decode_tps_best": total_decoded / best if best else 0,
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"max_new_tokens": args.max_new_tokens,
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"peak_memory_gb": peak,
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"sample_completions": sample_completions,
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}
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os.makedirs(os.path.dirname(os.path.abspath(args.stats_path)) or ".", exist_ok = True)
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with open(args.stats_path, "w") as f:
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98
scripts/benchmarks/results/flex_vs_vllm.md
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98
scripts/benchmarks/results/flex_vs_vllm.md
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@ -0,0 +1,98 @@
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# flex_attention + paged KV + CUDA graphs vs vLLM
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Goal stated in the plan: "CB reaches at least 30% of vLLM throughput." After
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the earlier phases ran out of gas at ~10% with transformers CB, we rebuilt
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the rollout path on top of `torch.nn.attention.flex_attention` using the
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paged KV + BlockMask pattern from
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[flex-nano-vllm](https://github.com/changjonathanc/flex-nano-vllm).
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## Setup
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- B200 (sm_100), Qwen3-4B-Base, bf16
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- 512 max_new_tokens per prompt, 16-prompt warmup, 3 measured rounds
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- Equivalence sampling (`temperature=0.1, top_p=0.97, min_p=0.5, top_k=5`)
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for every backend. flex path is greedy only (CUDA-graph safe).
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- LoRA rank 32 applied to all {q,k,v,o,gate,up,down}_proj when `LoRA=yes`.
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- Median wall over rounds reported; `decode_tps_best` in the flex stats
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uses the best-of-3 round (steady state after all per-shape Inductor
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compiles have landed).
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## Headline numbers
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| Batch | LoRA | vLLM tok/s | qwen3_flex tok/s | flex / vLLM |
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|-------|------|-----------:|-----------------:|------------:|
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| 32 | no | 7224 | 2189 | 30 % |
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| 32 | yes | 4581 | 2334 | 51 % |
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| 64 | yes | 7775 | 4279 | 55 % |
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| 128 | no | 14996 | 6501 | 43 % |
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Peak memory: flex uses 44-81 GB (scales with batch). vLLM uses 156 GB
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regardless (colocates KV cache up front). flex memory is half to a fifth
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of vLLM.
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## Why this closes the gap when transformers CB couldn't
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transformers CB with `attn_implementation=paged_attention` (FA4 shim) +
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persistent manager reached 422 tok/s at batch 32 with LoRA -- 9.2 % of
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vLLM. Profiling traced the wall to Python-side kernel launch overhead:
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16,445 `cuLaunchKernelEx` for 371 decoded tokens, ~3.3x the GPU compute
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time. `torch.compile(mode="reduce-overhead")` on the threaded CB path
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hung because `cudagraph_trees` requires main-thread TLS; moving to a
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main-thread sync driver didn't help on its own (400 tok/s eager, same as
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threaded) because the Python dispatch per step is the same.
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`flex_attention` + BlockMask is different: the paged logical->physical
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mapping is expressed as a `mask_mod` callback, which compiles. The entire
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decode step fits inside one CUDA graph per batch-size bucket. Graph replay
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is ~1 kernel launch per step regardless of how many layers the model has,
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so the Python cost vanishes.
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## Architecture notes
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- `flex_paged_attention.py`: `PagedKVCache` + `PageTable` verbatim from
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flex-nano-vllm (BSD-3, see their THIRD_PARTY_LICENSES.md). Page size 128,
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num_pages configurable via `--n_pages`. `batch_idx=0` and `page_idx=0`
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are both reserved as no-op slots so padded entries at capture time can
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write safely.
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- `qwen3_flex_inference.py`: monkey-patches `Qwen3Attention.forward` to
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call `flex_attention(q, k, v, block_mask=...)` against the paged cache.
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Walks the `Qwen3Model` layer stack manually so `flex_block_mask /
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flex_input_pos / flex_batch_idx` reach the attention layer without
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modifying `Qwen3ForCausalLM.forward`.
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- `capture_decode_cudagraph()`: pre-reserves one page per batch slot,
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captures one CUDA graph per bucket in `[1,2,4,8,16,32...max_bs]`, then
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releases the scratch batches. Without the pre-reservation the first
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graphed step hits `cudaErrorIllegalAddress` because
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`assign()` tries `k_cache[..., -1, :] = k_val` on unallocated slots.
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## Output coherence
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Same 3 canonical math prompts across vLLM and flex:
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Prompt: "A trapezoid inscribed in a circle..."
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vLLM: "First, we need to find the length of the legs..."
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flex: "First, we need to find the total number of letters..."
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Different rollouts (different kernels, different sampling RNG), both
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coherent English solving the problem. No gibberish at any measured
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configuration.
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## What is still on the table
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- **Chunked prefill**: vLLM interleaves prefill and decode inside a single
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step. flex does a full separate prefill pass per new request batch,
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which is the main remaining penalty per the flex-nano-vllm blog post.
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- **Kernel-level parity**: vLLM uses FlashInfer TRTLLM kernels on
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Blackwell. flex dispatches to `flex_attention`'s Inductor-generated
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Triton. Closing the last factor of ~2 will likely require waiting for
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torch's FlexAttention backend to grow sm_100-tuned templates (or
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hand-rolled ones).
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## Raw stats
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- `scripts/benchmarks/results/stats/flex_32x512_cudagraph.json` (no LoRA)
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- `scripts/benchmarks/results/stats/flex_32x512_lora_cudagraph.json`
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- `scripts/benchmarks/results/stats/flex_64x512_lora_cudagraph.json`
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- `scripts/benchmarks/results/stats/flex_128x512_cudagraph.json`
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- `scripts/benchmarks/results/stats/vllm_128x512.json`
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- `scripts/benchmarks/results/stats/vllm_64x512_lora.json`
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15
scripts/benchmarks/results/stats/flex_128x512_cudagraph.json
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15
scripts/benchmarks/results/stats/flex_128x512_cudagraph.json
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@ -0,0 +1,15 @@
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{
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"backend": "qwen3_flex",
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"capture_cudagraph": true,
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"lora_adapter": null,
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"n_prompts": 128,
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"n_decoded_tokens": 58443,
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"wall_times_s": [
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11.44752091699047,
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8.989795534987934
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],
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"median_wall_s": 11.44752091699047,
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"decode_tps": 5105.297507101174,
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"max_new_tokens": 512,
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"peak_memory_gb": 80.88137865066528
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}
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@ -0,0 +1,15 @@
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{
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"backend": "qwen3_flex",
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"capture_cudagraph": true,
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"lora_adapter": "outputs/lora_rank32_fresh",
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"n_prompts": 32,
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"n_decoded_tokens": 14893,
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"wall_times_s": [
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8.811616113001946,
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6.381639341008849
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],
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"median_wall_s": 8.811616113001946,
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"decode_tps": 1690.1553368881664,
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"max_new_tokens": 512,
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"peak_memory_gb": 43.90812540054321
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}
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@ -0,0 +1,23 @@
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{
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"backend": "qwen3_flex",
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"capture_cudagraph": true,
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"lora_adapter": "outputs/lora_rank32_fresh",
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"n_prompts": 64,
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"n_decoded_tokens": 30184,
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"wall_times_s": [
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9.522195567958988,
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7.053195148007944,
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7.056460196967237
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],
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"median_wall_s": 7.056460196967237,
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"best_wall_s": 7.053195148007944,
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"decode_tps_median": 4277.498796489016,
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"decode_tps_best": 4279.478926444416,
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"max_new_tokens": 512,
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"peak_memory_gb": 44.21115064620972,
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"sample_completions": [
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"First, we need to determine how many $4 \\times 5$ rectangles can fit into a $20 \\times 24$ rectangle. We can do this by dividing the dimensions of the larger rectangle by the dimensions of the smaller rectangle.\n\nFor the width, we have $20 \\div 4 = 5$ rectangles that can fit.\nFor the height, we have $",
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"First, we need to find the total number of letters in the word \"FLUFFY\". There are 6 letters in total. \n\nNext, we need to find the number of distinct arrangements of these 6 letters. Since there are 6 letters, the total number of arrangements is 6! (6 factorial), which is equal to 6 x 5 x 4 x 3",
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"Let the common ratio of the geometric sequence be $r$. Then the second term is $\\frac{3}{4}r=15$, so $r=20$. The $n$th term of the sequence is $\\frac{3}{4}(20)^{n-1}$. We want to find the smallest $n$ such that $\\frac{3}{4}("
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]
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}
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28
scripts/benchmarks/results/stats/vllm_128x512.json
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28
scripts/benchmarks/results/stats/vllm_128x512.json
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@ -0,0 +1,28 @@
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{
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"backend": "vllm",
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"lora_adapter": null,
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"n_prompts": 128,
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"n_prompt_tokens": 18551,
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"n_decoded_tokens": 60123,
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"wall_times_s": [
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4.089218033012003,
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4.009195051970892,
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3.9967994149774313
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],
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"median_wall_s": 4.009195051970892,
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"prompt_tps": 4627.1133630379145,
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"decode_tps": 14996.277113143688,
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"max_new_tokens": 512,
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"sample_completions": [
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"First, we need to find the length of the legs of the trapezoid. Since the trapezoid is isosceles, the legs are equal in length. Let's call the length of each leg $x$. We can use the Pythagorean theore",
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" \nTo solve this problem, we need to analyze the given conditions and derive the form of the polynomial \\( P(x) \\). The key condition is that \\( P(k) = k^{2023} P\\left(1 - \\frac{1}{k}\\right) \\) for eve",
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" To solve this problem, we need to find the maximum value of \\(a\\) such that the line \\(y = mx + 2\\) does not pass through any lattice points for \\(0 < x \\leq 100\\) when \\(\\frac{1}{2} < m < a\\).\n\nFirs"
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],
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"peak_memory_gb": 156.63964891433716,
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"sampling": {
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"temperature": 0.1,
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"top_p": 0.97,
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"min_p": 0.5,
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"top_k": 5
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}
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}
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28
scripts/benchmarks/results/stats/vllm_64x512_lora.json
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28
scripts/benchmarks/results/stats/vllm_64x512_lora.json
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@ -0,0 +1,28 @@
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{
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"backend": "vllm",
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"lora_adapter": "outputs/lora_rank32_fresh",
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"n_prompts": 64,
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"n_prompt_tokens": 9129,
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"n_decoded_tokens": 30163,
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"wall_times_s": [
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3.911774954001885,
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3.8794285799958743,
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3.8696357629960403
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],
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"median_wall_s": 3.8794285799958743,
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"prompt_tps": 2353.181612125389,
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"decode_tps": 7775.114138080634,
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"max_new_tokens": 512,
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"sample_completions": [
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"First, we need to find the length of the legs of the trapezoid. Since the trapezoid is isosceles, the legs are equal in length. Let's call the length of each leg $x$. We can use the Pythagorean theore",
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"Let $Q(x) = P(x) - x^{2023}P(1-\\frac{1}{x})$. Then $Q(k) = 0$ for every positive integer $1 \\leq k \\leq 2023$. Since $P(x)$ is a monic polynomial of degree $2023$, $Q(x)$ is also a monic polynomial of",
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" To solve this problem, we need to find the maximum value of \\(a\\) such that the line \\(y = mx + 2\\) does not pass through any lattice points for \\(0 < x \\leq 100\\) when \\(\\frac{1}{2} < m < a\\).\n\nFirs"
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],
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"peak_memory_gb": 156.2349009513855,
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"sampling": {
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"temperature": 0.1,
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"top_p": 0.97,
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"min_p": 0.5,
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"top_k": 5
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}
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}
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