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Fix handling tools without descriptions

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This commit is contained in:
Jeremiah Lowin 2025-05-27 09:08:24 -04:00
commit 05288fc507
3 changed files with 12 additions and 3 deletions
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2
src/fastmcp/resources/template.py
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@ -148,7 +148,7 @@ class ResourceTemplate(BaseModel):
f"URI parameters {uri_params} must be a subset of the function arguments: {func_params}"
)
description = description or fn.__doc__ or ""
description = description or fn.__doc__
if not inspect.isroutine(fn):
fn = fn.__call__

4
src/fastmcp/tools/tool.py
View file

@ -36,7 +36,7 @@ class Tool(BaseModel):
fn: Callable[..., Any]
name: str = Field(description="Name of the tool")
description: str = Field(description="Description of what the tool does")
description: str | None = Field(description="Description of what the tool does")
parameters: dict[str, Any] = Field(description="JSON schema for tool parameters")
tags: Annotated[set[str], BeforeValidator(_convert_set_defaults)] = Field(
default_factory=set, description="Tags for the tool"
@ -74,7 +74,7 @@ class Tool(BaseModel):
if func_name == "<lambda>":
raise ValueError("You must provide a name for lambda functions")
func_doc = description or fn.__doc__ or ""
func_doc = description or fn.__doc__
# if the fn is a callable class, we need to get the __call__ method from here out
if not inspect.isroutine(fn):